-36x^2+90x+54=0

Solution for -36x^2+90x+54=0 equation:

-36x^2+90x+54=0

a = -36; b = 90; c = +54;
Δ = b2-4ac
Δ = 902-4·(-36)·54
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15876}=126$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-126}{2*-36}=\frac{-216}{-72}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+126}{2*-36}=\frac{36}{-72}
=-1/2
$